@@ -0,0 +1,81 @@
+{
+"cells": [
+{
+"cell_type": "code",
+"execution_count": 53,
+"metadata": {},
+"outputs": [],
+"source": [
+"# How to find a list of strings in another list of strings without using for-loops (vectorized)\n",
+"# Via NumPy vectorization"
+]
+},
+{
+"cell_type": "code",
+"execution_count": 54,
+"metadata": {},
+"outputs": [],
+"source": [
+"import numpy as np"
+]
+},
+{
+"cell_type": "code",
+"execution_count": 55,
+"metadata": {},
+"outputs": [],
+"source": [
+"keys = np.array([\"the\", \"hi\", \"a\"])\n",
+"data = np.array([\"hello\", \"a\", \"world\", \"the\", \"python\", \"hi\", \"a\", \"sea\", \"the\"])"
+]
+},
+{
+"cell_type": "code",
+"execution_count": 56,
+"metadata": {},
+"outputs": [],
+"source": [
+"indices_matrix = np.core.defchararray.find(data, keys.reshape(-1,1) )\n",
+"indices = np.where(indices_matrix==0)[1]"
+]
+},
+{
+"cell_type": "code",
+"execution_count": 57,
+"metadata": {},
+"outputs": [
+{
+"name": "stdout",
+"output_type": "stream",
+"text": [
+"[3 8 5 1 6]\n"
+]
+}
+],
+"source": [
+"print(indices)"
+]
+}
+],
+"metadata": {
+"kernelspec": {
+"display_name": "Python 3",
+"language": "python",
+"name": "python3"
+},
+"language_info": {
+"codemirror_mode": {
+"name": "ipython",
+"version": 3
+},
+"file_extension": ".py",
+"mimetype": "text/x-python",
+"name": "python",
+"nbconvert_exporter": "python",
+"pygments_lexer": "ipython3",
+"version": "3.7.2"
+}
+},
+"nbformat": 4,
+"nbformat_minor": 2
+}