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1 | 1 | class Solution {
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2 |
| -public int[] restoreArray(int[][] adjacentPairs) { |
3 |
| -Map<Integer, List<Integer>> map = new HashMap<>(); |
4 |
| -for (int[] pair : adjacentPairs) { |
5 |
| -map.computeIfAbsent(pair[0], k -> new ArrayList<>()).add(pair[1]); |
6 |
| -map.computeIfAbsent(pair[1], k -> new ArrayList<>()).add(pair[0]); |
| 2 | +public int[] restoreArray(int[][] adjacentPairs) { |
| 3 | +int n = adjacentPairs.length + 1; |
| 4 | +Map<Integer, List<Integer>> map = new HashMap<>(); |
| 5 | +for (int[] pair : adjacentPairs) { |
| 6 | +map.computeIfAbsent(pair[0], k -> new ArrayList<>()).add(pair[1]); |
| 7 | +map.computeIfAbsent(pair[1], k -> new ArrayList<>()).add(pair[0]); |
| 8 | +} |
| 9 | +Queue<Integer> queue = new LinkedList<>(); |
| 10 | +int firstElement = map.entrySet() |
| 11 | +.stream() |
| 12 | +.filter(entry -> entry.getValue().size() == 1) |
| 13 | +.map(Map.Entry::getKey) |
| 14 | +.findFirst() |
| 15 | +.orElse(-1); |
| 16 | +queue.add(firstElement); |
| 17 | +Set<Integer> set = new HashSet<>(); |
| 18 | +int[] result = new int[n]; |
| 19 | +int idx = 0; |
| 20 | +while (!queue.isEmpty()) { |
| 21 | +int removed = queue.remove(); |
| 22 | +if (set.contains(removed)) { |
| 23 | +continue; |
| 24 | +} |
| 25 | +result[idx++] = removed; |
| 26 | +set.add(removed); |
| 27 | +queue.addAll(map.get(removed)); |
| 28 | +} |
| 29 | +return result; |
7 | 30 | }
|
8 |
| -int head = map.keySet().stream().filter(k -> map.get(k).size() == 1).findFirst().orElse(-1); |
9 |
| -Set<Integer> visited = new HashSet<>(); |
10 |
| -int[] result = new int[map.size()]; |
11 |
| -int idx = 0; |
12 |
| -Queue<Integer> queue = new LinkedList<>(); |
13 |
| -queue.add(head); |
14 |
| -while (!queue.isEmpty()) { |
15 |
| -int removed = queue.remove(); |
16 |
| -if (visited.contains(removed)) { |
17 |
| -continue; |
18 |
| -} |
19 |
| -result[idx++] = removed; |
20 |
| -visited.add(removed); |
21 |
| -queue.addAll(map.get(removed)); |
22 |
| -} |
23 |
| -return result; |
24 |
| -} |
25 | 31 | }
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